My answer would be correct if I didn't have that extra x variable. Why do I have it and how do I get rid of it?
Any input would be greatly appreciated!
Thanks in advance!
Your $\displaystyle du$ is wrong. It should be : $\displaystyle du = n \left( ln(x) \right) ^{n-1} {\color{red} \frac{1}{x}} dx$.
Recall that:
If $\displaystyle n \in R$ and $\displaystyle y=\left( f(x) \right)^n$ , then:
$\displaystyle y' = n \left( f(x) \right)^{n-1} {\color{red} f'(x)}$.