can someone please assist me real quick in taking the derivative of:
((2t+1)^(3/2))/3
thanks for your help!
I would write it as
$\displaystyle
\frac{1}{3} \left(2t + 1\right) ^{\frac{3}{2} }
$
then I think the derivative is...
$\displaystyle
\frac{1}{3} * \frac{3}{2}\left(2t + 1\right) ^{\frac{1}{2} } *2
$
So you take the derivative from the outer function ()^3/2 and then the derivative from the inner function 2t+1