The problem asks us to find the volume of the area bounded by y=-x^2+6x-8 and y=0 rotated around the x-axis by using the shells method.
I did this and got an answer of pi, to confirm the answer I used the disks method and got an answer of 16pi/15... please help by showing me how you do both methods.
using disks, the area of one disk is going to be pi*r^2 where r is going to be equal to y. A=pi(-x^2+6x-8)^2.... I set up the integral from 2 to 4 of pi(-x^2+6x-8)^2 dx = 16pi/15...
What am I doing wrong?