1. ## Solving This Integral?

1/2pi * integral(-infinity to infinity){(e^(-3ix+2)-5)*e^(-(x^2)/2) dx}

I'm stuck a few steps down

e^-3 * integral(-infinity to infinity){(e^-2ix-(x^2)/2 dx}

Not sure where to take it from here. Any help would be appreciated, thanks!

2. Originally Posted by soma
1/2pi * integral(-infinity to infinity){(e^(-3ix+2)-5)*e^(-(x^2)/2) dx}

I'm stuck a few steps down

e^-3 * integral(-infinity to infinity){(e^-2ix-(x^2)/2 dx}

Not sure where to take it from here. Any help would be appreciated, thanks!
I'm finding this very difficult to read...

Is it

$\frac{1}{2\pi}\int_{-\infty}^\infty{(e^{-3ix + 2} - 5)\,e^{-\frac{x^2}{2}}\,dx}$?

3. Yes you are correct. The "i" is throwing me off. Any help would be great, thanks.