$\displaystyle \int (2/x^5 + 16 / 11x) dx$
I'm not sure what I'm doing wrong here. I end up with $\displaystyle 2 \int 6/x^6 + 16 \int 2/11x^2$
if your power has more than one "elements" in it, put them in {}-brackets. [tex]x^-4[/tex] gives $\displaystyle x^-4$ while [tex]x^{-4}[/tex] gives $\displaystyle x^{-4}$
notice that Prove It had $\displaystyle \ln |x|$ not $\displaystyle \ln x$
and when you take anti-derivative, you drop the $\displaystyle \int$ signs...