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Math Help - Indefinite Integral

  1. #1
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    Indefinite Integral

    \int (2/x^5 + 16 / 11x) dx

    I'm not sure what I'm doing wrong here. I end up with 2 \int 6/x^6 + 16 \int 2/11x^2
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  2. #2
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    Quote Originally Posted by Archduke01 View Post
    \int (2/x^5 + 16 / 11x) dx

    I'm not sure what I'm doing wrong here. I end up with 2 \int 6/x^6 + 16 \int 2/11x^2

    try  <br />
2 \int x^{-5}~dx+ \frac{16}{11}\int \frac{1}{x}~dx <br /> <br />
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  3. #3
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    2 \int x^-4 /-4 + 16/11 \int x^-1 dx

    *the first integral is supposed to be x^-4 but it won't show up as a power when I put the math tags... sorry. I'm not sure what to do with the 2nd integral.
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  4. #4
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    Quote Originally Posted by Archduke01 View Post
    2 \int x^-4 /-4 + 16/11 \int x^-1 dx

    *the first integral is supposed to be x^-4 but it won't show up as a power when I put the math tags... sorry. I'm not sure what to do with the 2nd integral.
    Hint: \frac{d}{dx}(\ln{|x|}) = \frac{1}{x}...
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  5. #5
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    2 \int x^-4/-4 + 16/11 \int ln x + C

    Would that be the final answer?

    What is up with that x^-4?
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Archduke01 View Post
    2 \int x^-4/-4 + 16/11 \int ln x + C

    Would that be the final answer?

    What is up with that x^-4?
    if your power has more than one "elements" in it, put them in {}-brackets. [tex]x^-4[/tex] gives x^-4 while [tex]x^{-4}[/tex] gives x^{-4}

    notice that Prove It had \ln |x| not \ln x

    and when you take anti-derivative, you drop the \int signs...
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  7. #7
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    I love you Jhevon, thank you for your patience. I apologize for the stupid questions.
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