(1)/(t)^2 at t=a. The answer, but more importantly, solving using this formula: lim as t->a of [f(t)-f(a)] / t-a
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Originally Posted by ajcadoo (1)/(t)^2 at t=a. The answer, but more importantly, solving using this formula: lim as t->a of [f(t)-f(a)] / t-a $\displaystyle f(t)=\frac{1}{t^2}$. $\displaystyle f(a)=\frac{1}{a^2}$. $\displaystyle f'(a)=\lim_{t\to a} \frac{ \frac{1}{t^2} - \frac{1}{a^2} } { t-a }$. To evaluate it, start by making a common denominator in the numerator.
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