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Math Help - Spring Problem

  1. #1
    Junior Member Selim's Avatar
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    Spring Problem

    A spring of natural length 10 in. stretches 1.5 in. under a weight of 8 lb. Find the force function F(x).

    A spring of natural length 10 in. stretches 1.5 in. under a weight of 8 lb. Set up an integral to find
    the work done in stretching the spring from its natural length to a length of 14 in.

    A spring of natural length 10 in. stretches 1.5 in. under a weight of 8 lb. Find the work done in
    stretching the spring from its natural length to a length of 14 in.
    Help is always appreciated
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  2. #2
    Junior Member Selim's Avatar
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    F(x) = \frac{8lb}{15} = 5.3x

    \int{5.3x * dx} from 10 to 14 = 256 inch-pounds
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  3. #3
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    Quote Originally Posted by Selim View Post
    A spring of natural length 10 in. stretches 1.5 in. under a weight of 8 lb. Find the force function F(x).
    F(x)=kx

    Use 1.5 for x and 8 for F(x) to find k.

    You probably want to use the exact value k=16/3

    Quote Originally Posted by Selim View Post
    A spring of natural length 10 in. stretches 1.5 in. under a weight of 8 lb. Set up an integral to find
    the work done in stretching the spring from its natural length to a length of 14 in.
    x is the amount the spring stretches.
    When the spring is at its natural lenth of 10 in., x=0
    When the spring is at a length of 14 in., x=4
    Use those values of x as your limits of integration.
    Last edited by ione; February 22nd 2010 at 01:28 PM.
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  4. #4
    Junior Member Selim's Avatar
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    Thank you very much. I was wondering why that number was so odd. So I shall begin the integration from 0 until the distance stretched and it comes out to 128/3.
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  5. #5
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    Quote Originally Posted by Selim View Post
    Thank you very much. I was wondering why that number was so odd. So I shall begin the integration from 0 until the distance stretched and it comes out to 128/3.
    Good job, Selim
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