Results 1 to 3 of 3

Math Help - maximum value at given interval

  1. #1
    Super Member bigwave's Avatar
    Joined
    Nov 2009
    From
    honolulu
    Posts
    580

    Cool maximum value at given interval

     <br />
f(x)=\sqrt{1+x^3}
    find the maximum value of |f''(x)| on the given Interval of  [0,2]

    calculated f''(x) to be

     <br />
f''(x) = \frac{3x(x^3+4)}{4(x^3+1)^{3/2}}

    thot setting this to zero would give where the maximum value is

    but the answer is  f''|(\sqrt[3]{-10+\sqrt{108}})|=1.47

    graphing this can see that the top of the graph is 1.47 but don't see how this was derived.
    Last edited by bigwave; February 22nd 2010 at 11:17 AM. Reason: wording
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Nov 2009
    Posts
    50
    To find the max of f''(x) you have to set it's derivative (f'''(x)) to zero
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member bigwave's Avatar
    Joined
    Nov 2009
    From
    honolulu
    Posts
    580
    i did try this but did not get the answer as expected.
    f'''(x) is pretty complicated.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Maximum value of a function within an interval
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: November 28th 2011, 02:55 PM
  2. Replies: 2
    Last Post: June 9th 2010, 04:43 PM
  3. Replies: 8
    Last Post: May 23rd 2010, 11:59 PM
  4. Replies: 4
    Last Post: April 12th 2010, 09:36 PM
  5. Increasing interval and decreasing interval
    Posted in the Calculus Forum
    Replies: 4
    Last Post: February 24th 2006, 09:49 AM

Search Tags


/mathhelpforum @mathhelpforum