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- Feb 22nd 2010, 10:12 AM #1

- Joined
- Jan 2010
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- 2

- Feb 22nd 2010, 10:52 AM #2
domain ... $\displaystyle t^2+t \ge 0$

$\displaystyle

t(t+1) \ge 0

$

either $\displaystyle t \le -1$ , or $\displaystyle t \ge 0$

since the lower limit is $\displaystyle x = 1$ , $\displaystyle 2x \ge 0$ ... $\displaystyle x \ge 0$

$\displaystyle

\lim_{x \to \frac{1}{2}} F(x) = 0

$

$\displaystyle

S = \int_1^2 \sqrt{1 + [F'(x)]^2} \, dx

$

where $\displaystyle F'(x) = 2\sqrt{4x^2 + 2x}$