Without using Trig/Hyperbolic Substitutions.
And you must use the substitution method only.
I believed, its impossible to solve it.
No, the derivative of is
, not just
I doubt that you were taught that way!
Ted, I don't believe there is any way to do that other than either the trig or hyperbolic substitutions.
Of course, you could always look it up in a table of integrals. Does that count?