ok can you check my work and tell me if im on the right track...im getting the derivative @ 1 to be equal to 0. attached is a sample of my work, along with the formulas that im trying to use. thanks in advance.IMG.pdf
ok can you check my work and tell me if im on the right track...im getting the derivative @ 1 to be equal to 0. attached is a sample of my work, along with the formulas that im trying to use. thanks in advance.IMG.pdf
$\displaystyle y = x^{\cosh{x}}
$
logarithmic differentiation ...
$\displaystyle \ln{y} = \cosh{x} \cdot \ln{x}$
$\displaystyle \frac{y'}{y} = \cosh{x} \cdot \frac{1}{x} + \ln{x} \cdot \sinh{x}$
$\displaystyle y' = x^{\cosh{x}} \left[\frac{\cosh{x}}{x} + \ln{x} \cdot \sinh{x}\right]$