Thread: find the equation of the tangent line

1. find the equation of the tangent line

ok can you check my work and tell me if im on the right track...im getting the derivative @ 1 to be equal to 0. attached is a sample of my work, along with the formulas that im trying to use. thanks in advance.IMG.pdf

2. Originally Posted by slapmaxwell1
ok can you check my work and tell me if im on the right track...im getting the derivative @ 1 to be equal to 0. attached is a sample of my work, along with the formulas that im trying to use. thanks in advance.IMG.pdf
$y = x^{\cosh{x}}
$

logarithmic differentiation ...

$\ln{y} = \cosh{x} \cdot \ln{x}$

$\frac{y'}{y} = \cosh{x} \cdot \frac{1}{x} + \ln{x} \cdot \sinh{x}$

$y' = x^{\cosh{x}} \left[\frac{\cosh{x}}{x} + \ln{x} \cdot \sinh{x}\right]$