I'm lost since "a" and "b" are in the same formula
But I think if I take the derivative of the first one, I might be able to figure out "a" in the second.
Then I would just need a y value to find b.
Hello, Zanderist!
Find and so that the function: .
. . is both continuous and differentiable.
To be continuous, be equal on "both branches".
. .
. .
. . Hence: . .[1]
To be differentiable, must be equal on "both branches."
. .
. .
. . Hence: .
Substitute into [1]: .