Q. Use the bisection method to find an approximation to "the cubed root of 25" correct to within 10^-4.
Hey guys, so far i have been unable to find any info for finding an approximation to a value that is not the root of a function using the bisection method.
Any help is most appreciated.
Pretty sure i figured this one out, on p8 right now. If anyone wants to confirm with me i began by making f(x) = x^3 - 25 and then began solving for the root.