Thread: [SOLVED] use l'hospital's rule to find lim x->infinity lnx^2/((x^2)+1)

i have:

1/x^2
/
2x

because the f'(x) of lnx = 1/x so lnx^2 i think would be 1/x^2
f'(x) of (x^2)+1 is 2x

but, when i put 0 into the function... everything goes very wrong.

I tried taking the next derivative but that didn't work very well either.

I could use some ideas on what to do at this point.

Thanks
-star

edit: realized it was infinity and not 0.. i dont know how to delete the thread but as of this point i'm retrying the problem