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Math Help - [SOLVED] use l'hospital's rule to find lim x->infinity lnx^2/((x^2)+1)

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    [SOLVED] use l'hospital's rule to find lim x->infinity lnx^2/((x^2)+1)

    i have:

    1/x^2
    /
    2x

    because the f'(x) of lnx = 1/x so lnx^2 i think would be 1/x^2
    f'(x) of (x^2)+1 is 2x

    but, when i put 0 into the function... everything goes very wrong.

    I tried taking the next derivative but that didn't work very well either.

    I could use some ideas on what to do at this point.

    Thanks
    -star

    edit: realized it was infinity and not 0.. i dont know how to delete the thread but as of this point i'm retrying the problem
    Last edited by starbless; February 21st 2010 at 11:45 AM. Reason: miscalculuation
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