Originally Posted by

**Kakariki** Hey, I have a question that I do not know how to go about answering.

**Question:**

Let $\displaystyle y = g(h(x)) $where $\displaystyle h(x) = \frac{x^2}{x+2} $. If $\displaystyle g'(9/5) = -2 $, find dy/dx when $\displaystyle x = 3 $

**Attempted answer:**

Basically I have found the derivative of $\displaystyle h(x) = \frac{x^2}{x+2} $. Which is $\displaystyle h'(x) = \frac {-x^2}{(x + 2)^2} + \frac {2x}{(x+2)} $

I do not know what I am supposed to do with $\displaystyle g'(9/5) = -2 $. How do I find what the function g(x) is from that?

Thanks!