Results 1 to 3 of 3

Math Help - Derivative Help

  1. #1
    Junior Member
    Joined
    Jan 2010
    Posts
    54

    Derivative Help

    Hey Everyone:

    I was wondering if anyone could tell me where my error is.





    Thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,401
    Thanks
    1273
    Quote Originally Posted by evant8950 View Post
    Hey Everyone:

    I was wondering if anyone could tell me where my error is.





    Thanks
    First of all, don't put equals signs where things aren't equal.

    Specify where your derivative actually starts.


    Second, it becomes much easier if you cancel the common factor of v.

    So y = \frac{v^3 - 2v\sqrt{v}}{v} = v^2 - 2\sqrt{v} = v^2 - 2v^{\frac{1}{2}}.


    Therefore \frac{dy}{dv} = 2v - v^{-\frac{1}{2}} = 2v - \frac{1}{\sqrt{v}}.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Jan 2010
    Posts
    54
    Thanks
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. contuous weak derivative $\Rightarrow$ classic derivative ?
    Posted in the Differential Geometry Forum
    Replies: 2
    Last Post: April 22nd 2011, 02:37 AM
  2. Replies: 0
    Last Post: January 24th 2011, 11:40 AM
  3. [SOLVED] Definition of Derivative/Alt. form of the derivative
    Posted in the Calculus Forum
    Replies: 2
    Last Post: September 23rd 2010, 06:33 AM
  4. Derivative of arctan in a partial derivative
    Posted in the Calculus Forum
    Replies: 3
    Last Post: September 12th 2010, 01:52 PM
  5. Replies: 2
    Last Post: November 6th 2009, 02:51 PM

Search Tags


/mathhelpforum @mathhelpforum