[SOLVED] Okay I can't simplify this for the life of me

**thekrown** · February 20th 2010, 11:17 AM

5 - 3 / square root of 3

I'm unable to simplify this, at all!!!! Please help.

**skeeter** · February 20th 2010, 11:19 AM

Originally Posted by thekrown

5 - 3 / square root of 3

I'm unable to simplify this, at all!!!! Please help.

$5 - \frac{3}{\sqrt{3}} = 5 - \sqrt{3}$

**icemanfan** · February 20th 2010, 11:19 AM

This should probably go in the algebra section.

$5 - \frac{3}{\sqrt{3}} = 5 - \sqrt{3}$

**thekrown** · February 20th 2010, 11:34 AM

It's for my calculus class. I have to find derivatives and simplify them. You guys gave me the answer and I thank you for that, but I don't see how you got there.

**skeeter** · February 20th 2010, 11:36 AM

any number divided by its square root is its square root.

in other symbols ... $\frac{x}{\sqrt{x}} = \sqrt{x}$

**icemanfan** · February 20th 2010, 11:36 AM

$\frac{3}{\sqrt{3}} = \frac{3}{3^{1/2}} = 3^{1-1/2} = 3^{1/2} = \sqrt{3}$

**Archie Meade** · February 20th 2010, 12:06 PM

$2(2)=4,\ 2^2=4,\ \sqrt{4}\sqrt{4}=4$

$3(3)=9,\ 3^2=9,\ \sqrt{9}\sqrt{9}=9$

$\sqrt{3}\sqrt{3}=(\sqrt{3})^2=3$

therefore,

$\frac{3}{\sqrt{3}}=\frac{\sqrt{3}\sqrt{3}}{\sqrt{3 }}=\sqrt{3}\left(\frac{\sqrt{3}}{\sqrt{3}}\right)= \sqrt{3}(1)=\sqrt{3}$

**thekrown** · February 20th 2010, 12:43 PM

*smacks forehead* of course. Thank you all.

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