5 - 3 / square root of 3
I'm unable to simplify this, at all!!!! Please help.
$\displaystyle 2(2)=4,\ 2^2=4,\ \sqrt{4}\sqrt{4}=4$
$\displaystyle 3(3)=9,\ 3^2=9,\ \sqrt{9}\sqrt{9}=9$
$\displaystyle \sqrt{3}\sqrt{3}=(\sqrt{3})^2=3$
therefore,
$\displaystyle \frac{3}{\sqrt{3}}=\frac{\sqrt{3}\sqrt{3}}{\sqrt{3 }}=\sqrt{3}\left(\frac{\sqrt{3}}{\sqrt{3}}\right)= \sqrt{3}(1)=\sqrt{3}$