use a(t)=-32 feet per second squared as the acceleration due to gravity. a ball is thrown vertically upward from the ground with an initial velocity of 56 ft/s. for how many seconds will the ball be going upward.
so i know that s''(t)=a(t) and s'(t)=v(t) and that v(0)=56
i also know that integration is used in this problem
i tried it by integrating a(t) first to v(t) and getting -32t+C
using v(0)=56, i know that C=56 and that v(t)=-32t+56
I then integrated v(t) to s(t) and got s(t)=-16t^2 +56t+C and i don't know what to do from there