Originally Posted by

**lil_cookie** I have attempted to answer this question but come up with a number that just doesn't seem correct....please review my solution and let me know where I went wrong. Thanks!

Find f(2) if $\displaystyle f(1/3) = 2$ and $\displaystyle f ' (x) = e^{3x+2}-3x$

my solution:

= $\displaystyle \frac{1}{3}e^{3x+2}+C$

and since f(1/3) = 2 then: 2 = $\displaystyle \frac{1}{3}e^{3(1/3)+2}+C$

and solving for C gives me a not so great number.

please let me know where I went wrong....thanks!