$\displaystyle \int -\cos({\cos({\tan (x)})})\cdot \sin{\tan(x)}\cdot \sec ^2(x)dx$ I have absolutely no clue how to start.
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Originally Posted by Keithfert488 $\displaystyle \int -\cos({\cos({\tan (x)})})\cdot \sin{\tan(x)}\cdot \sec ^2(x)dx$ I have absolutely no clue how to start. $\displaystyle u = \cos(\tan{x})$ $\displaystyle du = -\sin(\tan{x}) \cdot \sec^2{x} \, dx $ substitute ...
Wow that's a lot simpler than it looks. So its just $\displaystyle \sin({\cos({\tan({x})})})$?
Originally Posted by Keithfert488 Wow that's a lot simpler than it looks. So its just $\displaystyle \sin({\cos({\tan({x})})})$? check it ... $\displaystyle \frac{d}{dx} \sin[\cos(\tan{x})] = ?$
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