if f in sqrt(f(x)) is differentiable, would it equal to f'(x) ------ 2sqrt[f(x)] ?
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trying this out with x^3, i get 2(x^3)-1*(3x^2), and i think this would yield.... 3x^2 ------ 2(x^3) I know this is a dumb simplification problem but i just wanted some clarification. thanks.
Originally Posted by Evan.Kimia if f in sqrt(f(x)) is differentiable, would it equal to f'(x) ------ 2sqrt[f(x)] ? Let I get the same answer as you but I'm not 100% confident it's right
Originally Posted by Evan.Kimia trying this out with x^3, i get 2(x^3)-1*(3x^2), and i think this would yield.... 3x^2 ------ 2(x^3) I know this is a dumb simplification problem but i just wanted some clarification. thanks. Not quite right. You should have: An easier way is to realize that So you get right to:
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