what do I get when I integrate x^2.5 dx Please?
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Originally Posted by wolfhound what do I get when I integrate x^2.5 dx Please? Integration without bounds is equivalent to solving for an antiderivative. Antiderivative of functions of the form, , amounts to
Originally Posted by vince Integration without bounds is equivalent to solving for an antiderivative. Antiderivative of functions of the form, where n is real, amounts to Sorry but I don't have a clue what your on about!!!!!!!! Could someone please show me the answer this part is delaying me Help please!
Originally Posted by wolfhound Sorry but I don't have a clue what your on about!!!!!!!! Could someone please show me the answer this part is delaying me Help please! dude, ...clear now?
My problem is what do I raise x^2.5 to? (x^?/?)
so its x to the power of 3.5 divided by 3.5 + C ?
+ C
Originally Posted by vince Integration without bounds is equivalent to solving for an antiderivative. Antiderivative of functions of the form, , amounts to .
Originally Posted by Ted . but of course, making sure if anyone was paying attention.
But you said where n is real.
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