Integrate 1/(x^3+x^2+x) dx I tried factoring the bottom and using the A/Factor1+B/Factor2 technique but couldn't really get anywhere with that.
Integrate 1/(1+cosx) dx I feel like this is simple but I can't figure it out.
Thanks for your help.
Integrate 1/(x^3+x^2+x) dx I tried factoring the bottom and using the A/Factor1+B/Factor2 technique but couldn't really get anywhere with that.
Integrate 1/(1+cosx) dx I feel like this is simple but I can't figure it out.
Thanks for your help.
Like you said, you would need to use partial fractions:
You can verify that:
So our new integral is:
For the second term, you're going to have to complete the square and use a trigonometric substitution. See how far you can go with that one. It'll probably be pretty long and tedious.
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For the second integral, multiply both top and bottom by .
Now use a few trigonometric identities to get your integral to become:
which are standard ones.