Hi,

I am trying to solve ∫ln(t)^2 dt. I already solved part of the integral, however I don't know how to complete the exercise. Can someone help me? Thanks.

∫ln(t)^2 dt

u=ln(t)^2 dv=dt

du=2ln(t)*(1/t)dt v =t

t*ln(t)^2-∫t*2ln(t)*(1/t)dt

t*ln(t)^2-∫(t*2ln(t)/t) dt

t*ln(t)^2-∫(2ln(t)) dt