Hello
How do I integrate x^4(1+x^2)^2 I know its: u dv/dx dx=uv- inte v dudx dx
so I know the integral of x^4 is (x^5)/5 but what the hell is the integral of dv/dx dx?
please help!
I wouldn't do this via parts. As the exponent is low expand the binomial and then distribute the x^4
Which is relatively simple to evaluate
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If you want integration by parts anyway prepare for some hard work
and more integration by parts ensues