Show that:

.

Am sure, there is a trick somewhere.

sure, we will not differentiate it normally.

I rewrite the function as:

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- Feb 18th 2010, 09:25 AMTedDifferentiation's Proof ..
Show that:

.

Am sure, there is a trick somewhere.

sure, we will not differentiate it normally.

I rewrite the function as: - Feb 18th 2010, 09:33 AMCalculus26

the function reduces to 1- 1/2sin(2x)

convert to sines and cosines and combine into a single term

recall a^3 + b^3 = (a+b) (a^2 -ab +b^2) - Feb 18th 2010, 09:55 AMSoroban
Hello, Ted!

You're right . . . We're expected to simplify the function first.

Quote:

.

We have: .

. . . . . .

. . . . . .

. . . . . .

. . . . . .

. . . . . .

. . . . . .

. . . . . .

*Now*differentiate it!

Edit: Ah, Calculus 26 beat me to it . . . *sigh*

. - Feb 18th 2010, 10:10 AMvince