Show that: . Am sure, there is a trick somewhere. sure, we will not differentiate it normally. I rewrite the function as:
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the function reduces to 1- 1/2sin(2x) convert to sines and cosines and combine into a single term recall a^3 + b^3 = (a+b) (a^2 -ab +b^2)
Hello, Ted! You're right . . . We're expected to simplify the function first. . We have: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Now differentiate it! Edit: Ah, Calculus 26 beat me to it . . . *sigh* .
Originally Posted by Soroban Hello, Ted! You're right . . . We're expected to simplify the function first. We have: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Now differentiate it! Edit: Ah, Calculus 26 beat me to it . . . *sigh* . the colors the indenting... ...too much
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