How would I go about doing a problem like this? Find dy/dx for y= x^(9/8) Just one more thing, where can I find a list to all the commands for MATH tags?
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Originally Posted by Zanderist How would I go about doing a problem like this? Find dy/dx for y= x^(9/8) If , where is a constant, then Just one more thing, where can I find a list to all the commands for MATH tags? see the sticky threads here
Originally Posted by Jhevon If , where is a constant, then My problem as it was The "1" by the way is with the Exponent. So with that said it should come out to be:
Originally Posted by Zanderist The "1" by the way is with the Exponent. So with that said it should come out to be:
y= x^(9/8) iff ln(y)=ln(x^(9/8)) ln(y)=(9/8)ln(x), property of logs. (dy/dx)(1/y)=(9/8)(1/x) (dy/dx)=y(9/8)(1/x) (dy/dx)=(x^(9/8))(9/8)(1/x)
Originally Posted by Chris11 y= x^(9/8) iff ln(y)=ln(x^(9/8)) ln(y)=(9/8)ln(x), property of logs. (dy/dx)(1/y)=(9/8)(1/x) (dy/dx)=y(9/8)(1/x) (dy/dx)=(x^(9/8))(9/8)(1/x) and x^(9/8)(1/X)= x^(1/8) as before. Do you always use logarithms to differentiate x^n?