# Thread: volume of a solid under a curve

1. ## volume of a solid under a curve

Find the volume of the resulting solid if the region under the curve from to is rotated about the x-axis.

Would the volume of this just be the integral from 0 to 1?

2. Originally Posted by cdlegendary
Find the volume of the resulting solid if the region under the curve from to is rotated about the x-axis.

Would the volume of this just be the integral from 0 to 1?
no. the integral of the function gives you the net area under the curve.

use the disk method. $V = \pi \int_0^1 \left( \frac 1{x^2 + 3x + 2} \right)^2~dx$