I'm not getting the correct answer. Are there any mistakes? If so, could someone please correct them for me?
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Originally Posted by yzobel I'm not getting the correct answer. Are there any mistakes? If so, could someone please correct them for me? just one... $\displaystyle -\frac{3}{2}\int_{0}^1Sin(4t)dt=\frac{3}{2}{\left[\frac{Cos(4t)}{4}\right]^1}_0$
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