Hi
5a) Let f defined by
f(x) = 1 for x not equal to 0
f(0) = -1
f is clearly not continuous at 0
g(x) = f(x) f(x) = 1 for all x real, therefore is continuous at 0
h(x) = f(f(x)) = 1 as well
Hello! I have been busting my head over this question and can't for some reason solve it. Can anyone explain to me how it works or how to compute the answer.The question I am reffering to is number 5 both A and B
Thx in advance!
his answer is very good, however its just the part where it says f(fx) that i get slightly confused at. Like what exactly are we plugging in. Is it like based off the original rule
1 for x does not equal 0
f(x)= -1 for x equals 0
so when we do f(fx) is that essentialy defined as
h(x)= ????? for x=0
????? for x does not equal 0
so f(f(0) is f(-1)---> which is = 1
and f(f(4) is f(1)---> which is = 1
so h(x)=1
I'm I on the right track?