Thread: find the area between 2 functions

g(x) = 4/(2-x) ; y = 4 ; x = 0 i know how to integrate i would really like to see the setup of this problem. i have my integral running from 0 to 1 and the function is g(x) = 4/2-x? no wait thats not right, it should be 4 - 4/(2-x) dx. ok so is my setup right? thanks in advance.

Originally Posted by slapmaxwell1

g(x) = 4/(2-x) ; y = 4 ; x = 0 i know how to integrate i would really like to see the setup of this problem. i have my integral running from 0 to 1 and the function is g(x) = 4/2-x? no wait thats not right, it should be 4 - 4/(2-x) dx. ok so is my setup right? thanks in advance.

This is the setup:



So, I'd say you got the setup correct. Good job!

Hope I helped you there