Thread: derivative question

im doing question

f(x) = (x^2 - [e^(2x)] + [sin^3 (x)])^7, find f'(x)

so far,
f'(x)= 7(x^2 - [e^(2x)] + [sin^3 (x)])^6 * (x^2 - [e^(2x)] + [sin^3 (x)])'
= 7(x^2 - [e^(2x)] + [sin^3 (x)])^6 *@@@@@@@@@@@@@@

for @@@@@@@@...
i know i have to derivate (x^2 - [e^(2x)] + [sin^3 (x)])'
i was wondering if i just derivate like 2x - 2e^2x + 3(sinx)^2 (cosx) ?

if so, do i have to derivate "x" from"
(sinx)^3
3(sinx)^2 (cosx) <--- from here, do i have to derivate "x"? like 3(sinx)^2 (cosx)(x)' ?

Originally Posted by haebinpark

im doing question

f(x) = (x^2 - [e^(2x)] + [sin^3 (x)])^7, find f'(x)

so far,
f'(x)= 7(x^2 - [e^(2x)] + [sin^3 (x)])^6 * (x^2 - [e^(2x)] + [sin^3 (x)])'
= 7(x^2 - [e^(2x)] + [sin^3 (x)])^6 *@@@@@@@@@@@@@@

for @@@@@@@@...
i know i have to derivate (x^2 - [e^(2x)] + [sin^3 (x)])'
i was wondering if i just derivate like 2x - 2e^2x + 3(sinx)^2 (cosx) ?

if so, do i have to derivate "x" from"
(sinx)^3
3(sinx)^2 (cosx) <--- from here, do i have to derivate "x"? like 3(sinx)^2 (cosx)(x)' ?

I explained to you about the derivative of the 'x' in the other thread. You understand it, right?




I've pointed out the places where I've multiplied something because of the chain rule with . Do you see how that works. If you need anymore help, feel free to ask.

Hope I helped you