Find the points on the graph f(x)=2x that is closest to the point (1,0) . How would you go about this?
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Originally Posted by av8or91 Find the points on the graph f(x)=2x that is closest to the point (1,0) . How would you go about this? The square distance of an arbitary point from is: Now substitute from for either or then differentiate and set the derivative to zero, and solve. CB
Originally Posted by av8or91 Find the points on the graph f(x)=2x that is closest to the point (1,0) . How would you go about this? A general point on the graph of is of the form , so the distance between such a point and (1,0) is; . Well, do some order here and check this is a function of x so to find is extreme points you have to... Tonio
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