I don't know how to do the attached question although I do know the general formula to use.
Let $\displaystyle u = t+9$
$\displaystyle du = dt$
Therefore, when we sub in these values:
$\displaystyle \int \frac{dt}{(t+9)^2} = \frac{du}{u^2}$
That is a much simpler integral, Remember to put in the constant of integration and sub t for u in the integrated expression