show that convolution is commutative, f * g = g * f cheers
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Originally Posted by hugolovesmaths show that convolution is commutative, f * g = g * f cheers $\displaystyle (f*g)(t)=\int_{-\infty}^{\infty}f(\tau)g(t-\tau) \; d\tau$ Now change variables using $\displaystyle u=t-\tau$. CB
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