1.) Answer Key: 2.) Answer Key: Thanks a lot!!!!
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Here's the first one
Originally Posted by ^_^Engineer_Adam^_^ 1.) Answer Key: 2.) Answer Key: Thanks a lot!!!! um, for the second one, i think you gave the answer key twice
The question is integral of sin(x)*(sin(cosx))dx answer key: (cos(cos(x)) + C
Originally Posted by Krizalid Here's the first one that's nice. i didn't even consider substitution. i ended up trying trig substitution, which was hell. but things seemed to be working out nicely until i ended up with x^4/4(x^2 + 4)^2 which is wrong.
Originally Posted by ^_^Engineer_Adam^_^ The question is integral of sin(x)*(sin(cosx))dx This is a really easy one Just set u = cos x and du = - sin x dx, therefore the integral becomes to -sin udu, which yields cos u + c and we've got that cos (cos x) + c.
Originally Posted by ^_^Engineer_Adam^_^ The question is integral of sin(x)*(sin(cosx))dx answer key: (cos(cos(x)) + C we proceed by substitution: let u = cos(x) => du = -sin(x) dx => - du = sin(x) dx so our integral becomes: - int{sin(u)}du = cos(u) + C = cos(cos(x)) + C too late
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