Need help on finding the surface area generated by revolving the curve
y=square root of 25-x^2 around the X-axis for -3 ≤ x ≤ 4
Thank you
As the curve revolves around the x-axis, each point on graph of the function traces out a circle, with f(x) as radius.
To calculate the surface area, the circle circumferences are integrated.
Hence, the curved surface area is....
You may or may not want to include the circular side faces.