Need help on finding the surface area generated by revolving the curve

y=square root of 25-x^2 around the X-axis for -3 ≤ x ≤ 4

Thank you

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- Feb 16th 2010, 12:08 PMmacadamianchicaFind the surface area generated by revolving the curve
Need help on finding the surface area generated by revolving the curve

y=square root of 25-x^2 around the X-axis for -3 ≤ x ≤ 4

Thank you - Feb 16th 2010, 01:13 PMblertta
- Feb 16th 2010, 01:18 PMArchie Meade
As the curve revolves around the x-axis, each point on graph of the function traces out a circle, with f(x) as radius.

To calculate the surface area, the circle circumferences are integrated.

Hence, the curved surface area is....

You may or may not want to include the circular side faces. - Feb 17th 2010, 02:34 AMblertta
- Feb 17th 2010, 02:45 AMArchie Meade
This is not the "integration of a function problem".

It's a 3-dimensional "surface of revolution".