Thread: Find length of a plane curve y=2x^3/2 from x=4 to x=16

I need help with finding the length of a plane curve y=2x^3/2 from x=4 to x=16

Thank you

straightforward.

show us what you've done to see where's your problem.

So I did a integral on the square root of 1+[F'(x)]^2 dx from 4 to 16 and then I used a u substitution for 1+9x and got 112.66. But not sure if I did it right.

it's correct.