Can someone help me integrate: ∫ x^3/X^2+1 dx from 1 to 2 Thank you
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Once you integrate you get x^2/2+x substitude x'es with 2 and the result minus the substitution of 1 which equals to 5/2 asuming that the "+1" is not in the denominator Originally Posted by macadamianchica Can someone help me integrate: ∫ x^3/X^2+1 dx from 1 to 2 Thank you
Observe that . Therefore,
Here's an alternative method (you'll get the same result). Let so that . Then we have: and . So:
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