Does anyone know how to do the above integral? I'm stumped on where to even start.
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Can you do it from here?
thanks for the help. From there you would just do u-sub with sinx, if I'm not mistaken
Originally Posted by cdlegendary thanks for the help. From there you would just do u-sub with sinx, if I'm not mistaken Yes, that will work. Then you have
And then subbing back in after taking the integral would give you ((9sinx^5)/5)-(3sinx^3)+C thanks for the help
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