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Math Help - Differentiating E

  1. #16
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Xavier20 View Post
    y' = [sin(2t)tcos(2t)*2]e^(tsin(2t))

    Yeah. I forgot to add the + sign between the sin(2t) and tcos(2t) and didn't bring the *2 out infront of the tcos(2t) in my chain rule.

    Thanks for sorting that out though.

    It should be:

    y' = [sin(2t) + 2tcos(2t)]e^(tsin(2t))
    correct. i guess you're a genius with derivatives involving e now, but practice a few more problems to make sure

    good luck!
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  2. #17
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    Thanks a lot. =)
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