Originally Posted by

**anderson** hi everyone

im stuck with this question, need help to clarify..

Determine this series is absolutely convergent or diverges by using ratio test.

$\displaystyle \sum ^\infty_{n=1}$$\displaystyle \frac{(-1)^n e^\frac{1}{n}}{n^3}$

i manage to get this

$\displaystyle \frac{\frac{(-1)^{n+1} e^\frac{1}{n+1}}{(n+1)^3}}{\frac{(-1)^n e^\frac{1}{n}}{n^3}}$

$\displaystyle \frac{-(n^3)e^\frac{1}{n+1}}{e^\frac{1}{n+1}(n+1)^3}$

how do i complete this working, out of ideas.need help.

really appreciate all your help & guidance, thank you in advance for all your help & support.