For the function f(x) = 2√(2x-2), find delta such that |2√(2x-2) - 4| < 0.5 whenever |x - 3| < delta. (Determine how close x must be to 3 to ensure that f(x) is within 0.5 of 4) Any insight onto this problem? I don't know where to start really
Follow Math Help Forum on Facebook and Google+
Originally Posted by Intrusion For the function f(x) = 2√(2x-2), find delta such that |2√(2x-2) - 4| < 0.5 whenever |x - 3| < delta. (Determine how close x must be to 3 to ensure that f(x) is within 0.5 of 4) Any insight onto this problem? I don't know where to start really What have you tried?
2√(2x-2) < 3.5 √(2x-2) = 3.5/2 2x -2 = (3.5/2)^2 x = 2.53125 2√(2x-2) < 4.5 √(2x-2) = 4.5/2 2x -2 = (3.5/2)^2 x = 3.53125 3.53125 - 3 = .53125 3 - 2.53125 = .46875 So .46875 is delta.
View Tag Cloud