Consider the boundaries of the shaded region given (see attached graph).
Find the area A of this region by writing x as a function of y and integrating with respect to y.
I am not sure if I am doing this right, but this is what I did...
I took the derivative of 10 ^ 1/5 and assumed the integral was from 0 to 1 (since it shows on the graph I guess)
= 10^ 6/5 divided by 6/5 to get 50/6 x^ 1/5, plugged in the values and got 50/6, which is about 8.33 = area..is that right? But I'm confused to how to write it as a function. Is it like the integral (0,1) 50/6x ^ 6/5?