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Thread: Help finding the limit of this series

  1. February 15th 2010, 03:57 PM #1
    paupsers
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    Help finding the limit of this series

    \sum_{k=2}^\infty ln\frac{k^2-1}{k^2}

    I'm trying to figure out how to find the limit of this series. Any advice?
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  2. February 15th 2010, 04:30 PM #2
    General
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    Quote Originally Posted by paupsers View Post
    \sum_{k=2}^\infty ln\frac{k^2-1}{k^2}

    I'm trying to figure out how to find the limit of this series. Any advice?
    \frac{k^2-1}{k^2}=\frac{k-1}{k} \,\ \frac{k+1}{k}.

    Apply:

    ln(ab)=ln(a)+ln(b). for a,b>0.
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