Results 1 to 2 of 2

Math Help - Help finding the limit of this series

  1. #1
    Member
    Joined
    Mar 2009
    Posts
    168

    Help finding the limit of this series

    \sum_{k=2}^\infty ln\frac{k^2-1}{k^2}

    I'm trying to figure out how to find the limit of this series. Any advice?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member General's Avatar
    Joined
    Jan 2010
    From
    Kuwait
    Posts
    562
    Quote Originally Posted by paupsers View Post
    \sum_{k=2}^\infty ln\frac{k^2-1}{k^2}

    I'm trying to figure out how to find the limit of this series. Any advice?
    \frac{k^2-1}{k^2}=\frac{k-1}{k} \,\ \frac{k+1}{k}.

    Apply:

     ln(ab)=ln(a)+ln(b). for a,b>0.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Finding a limit. Finding Maclaurin series.
    Posted in the Calculus Forum
    Replies: 2
    Last Post: May 18th 2010, 10:04 PM
  2. Finding limit of function using series expansion
    Posted in the Differential Geometry Forum
    Replies: 3
    Last Post: March 26th 2010, 10:32 AM
  3. Replies: 1
    Last Post: March 21st 2010, 10:42 AM
  4. Finding a limit using Maclaurin Series
    Posted in the Calculus Forum
    Replies: 1
    Last Post: November 2nd 2009, 01:23 AM
  5. Finding a limit of two given series
    Posted in the Calculus Forum
    Replies: 2
    Last Post: October 29th 2005, 12:02 PM

Search Tags


/mathhelpforum @mathhelpforum