# Math Help - Help finding the limit of this series

1. ## Help finding the limit of this series

$\sum_{k=2}^\infty ln\frac{k^2-1}{k^2}$

I'm trying to figure out how to find the limit of this series. Any advice?

2. Originally Posted by paupsers
$\sum_{k=2}^\infty ln\frac{k^2-1}{k^2}$

I'm trying to figure out how to find the limit of this series. Any advice?
$\frac{k^2-1}{k^2}=\frac{k-1}{k} \,\ \frac{k+1}{k}$.

Apply:

$ln(ab)=ln(a)+ln(b)$. for $a,b>0$.