Equation of Tangent

**ntrantrinh** · February 15th 2010, 03:36 PM

Hey, just started this year's calc class and I have a question:

If $\dfrac{f(x)g(x)} {h(x)}$

Write the equation of the tangent to $y$ and $x = 3$

**pickslides** · February 15th 2010, 03:59 PM

assuming

If $y(x) = \dfrac{f(x)g(x)}{h(x)}$

then the tangent will be $y- y(3) = y'(3)(x-3)$

**ntrantrinh** · February 15th 2010, 05:46 PM

Thanks for the reply, but can you tell me how you got to that answer?

**pickslides** · February 15th 2010, 06:11 PM

The equation of a tangent to a function y at x = 3 can be given by

$y- y(3) = y'(3)(x-3)$

which is a straight line and comes from the form

$y- y_1 = m(x-x_1)$

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