Find the limit at infinity.
g(z) = 4z^6 - 7z^3 / (z^2 -4)^3
Not sure how to do this...please help.
Not sure if this helps and plus I am also really new to these forums, but I remember my teacher taught me this:
Look at the highest power in the numerator and in the denominator.
1) If they both have the same highest power, the ratio between the numerator and the denominator is the limit.
2)If the denominator has a higher power, the limit goes to zero
3)If the numerator has a higher power, the limit goes to infinity
ex1) $\displaystyle 5x^2 / x^2$ limit goes to 5
ex2) $\displaystyle 5x / x^2 $ limit goes to zero
ex3) $\displaystyle 5x^2 / x$ limit goes to infinity
So for your problem, try to compare the highest powers and see what happens. I hope this may be of some help to you and I hope I remembered right
Yes, usually when I did these kinds of problems and found an answer I would check it with this approach:
Plug in a very large value into the equation (such as 500,000 or something), and see what happens. Make sure that you just don't go about doing this to find the answer, because you need to understand how that answer came to be. For this problem, plugging in a large value such as 500,000 would lead to the limit, 4.
$\displaystyle \frac{4z^6-7z^3}{z^6-12z^4+48z^2-64}$
now divide both numerator and denominator by $\displaystyle z^6$
$\displaystyle \frac{\frac{4z^6}{z^6}-\frac{7z^3}{z^6}}{\frac{z^6}{z^6}-\frac{12z^4}{z^6}+\frac{48z^2}{z^6}-\frac{64}{z^6}}$
$\displaystyle \frac{4-\frac{7}{z^2}}{1-\frac{12}{z^2}+\frac{48}{z^4}-\frac{64}{z^6}}$
So the limit will be 4.