Find the indefinite integral: $\displaystyle \int (1+\frac{1}{t})^{3}(\frac{1}{t^2})dt$ Perhaps I'm just missing the obvious here, but I can't even determine what to set u to. Any help?
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Originally Posted by xfriendsonfirex Find the indefinite integral: $\displaystyle \int (1+\frac{1}{t})^{3}(\frac{1}{t^2})dt$ Perhaps I'm just missing the obvious here, but I can't even determine what to set u to. Any help? Set u=$\displaystyle 1+\frac{1}{t}$ then $\displaystyle du = \frac{-1}{t^2}dt$ Clear now?
Crystal. I feel stupid now. Haha. Thanks!
Originally Posted by xfriendsonfirex Crystal. I feel stupid now. Haha. Thanks! yeah, i feel bad for answering so directly. i should have hinted instead. it was really something you should have seen. you are nowhere near ready for an exam, based on this, my friend.
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